Ron
29-10-08, 12:41 AM
I found this pretty interesting from calculus, I'm not sure if I explain it right but if I do...It's awesome!!!
Okay so...
Theorem: 2 * 2 != 4
Proof:
2 = 2 ^ 1
Product Law states: Derivatives of 2 ^ 1 = 1(bring the exponent down), the 2 becomes 0 because there is no exponent
Thus, 2 ^ 1 = 1 * 0
Therefore, We have:
1 times(*) the derivative of the 2nd number plus(+) 1 times(*) the derivative of the first number
Thus, we have:
1 * 0 + 1 * 0 = 0 + 0 = 0
Therefore, 2 * 2 = 0
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Okay so...
Theorem: 2 * 2 != 4
Proof:
2 = 2 ^ 1
Product Law states: Derivatives of 2 ^ 1 = 1(bring the exponent down), the 2 becomes 0 because there is no exponent
Thus, 2 ^ 1 = 1 * 0
Therefore, We have:
1 times(*) the derivative of the 2nd number plus(+) 1 times(*) the derivative of the first number
Thus, we have:
1 * 0 + 1 * 0 = 0 + 0 = 0
Therefore, 2 * 2 = 0
Adapter from Internet